Count of Smaller Numbers After Self

Given an integer array nums, return an integer array counts where counts[i] is the number of smaller elements to the right of nums[i].

Constraints

  • 1 <= nums.length <= 10^5
  • -10^4 <= nums[i] <= 10^4
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class Solution:
def countSmallerAfterSelf(self, nums: List[int]) -> List[int]:
Console

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