Sort List

Given the head of a linked list, return the list after sorting it in ascending order.

Constraints

  • The number of nodes in the list is in the range [0, 5 * 10^4].
  • -10^5 <= Node.val <= 10^5
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# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next

class Solution:
def sortList(self, head: ListNode) -> ListNode:

Console

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